Hence the fm delta functions have strengths given by

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Unformatted text preview: to n ∈ {−3, −2, −1, 0, 1, 2, 3} will be passed. The modulation index of this signal is β = ∆fmax = 5. Hence, the fm delta functions have strengths given by Jn (5), where n ∈ {−3, −2, −1, 0, 1, 2, 3}. The power at the output of the filter, divided by the total power is then: 3 ∞ ￿ ￿ Pout 2 = Jn (β ) / Jn (β )2 Pin n=−∞ n=−3 The sum in the denominator is equal to 1.0 (you can either look this up, or just do the sum over a large number of terms to show that it converges to one as the number of included terms...
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This homework help was uploaded on 03/13/2014 for the course ECE 453 taught by Professor Staff during the Spring '08 term at University of Illinois, Urbana Champaign.

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