hwset2solution

# The carrier frequency will be at 2 1 2 w and the upper

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Unformatted text preview: at the lower edge of the passband of H (ω − ω2 ), then only the upper sideband will be passed. To make this happen, set ω2 − ω1 = ω2 − π W , or ω1 = π W (f1 = W/2). The other alternative would be to place the center of M (ω − ω2 + ω1 ) at the upper edge of the passband of H (ω − ω2 ) - but this requires that ω2 − ω1 = ω2 + π W , which cannot be done (ω1 is a positive number). Thus, provided that ω1 = π W (f1 = W/2), choosing the upper sign will give USB. The carrier frequency will be at ω2 − ω1 = ω2 − π W and the upper edge of the transmitted spectrum will be at ω2 − ω1 + 2π W = ω2 + π W . S (ω ) = 1c - In part b, we determined that choosing the + sign yields USB. If the - sign is chosen then S (ω ) = 1 1 M (ω + ω2 + ω1 )H (ω + ω...
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## This homework help was uploaded on 03/13/2014 for the course ECE 453 taught by Professor Staff during the Spring '08 term at University of Illinois, Urbana Champaign.

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