C the eective capacitance of a real capacitor is

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Unformatted text preview: ill be purely reactive, with reactance given by 1 XC = ω L − . ωC The effective capacitance of a real capacitor is obtained from − 1 1 = ωL − . ω Cef f ωC So Cef f = C C = 2 1 − ω 2 LC 1 − f2 f o where fo = 1 √ 2π LC . b. For the given values (C = 300pF and L = 20nH), fo =64.975 MHz. At 10 MHz Cef f = pF. At 40 MHz, Cef f = 300 1− 402 64.9752 300 1− 102 64.9752 = 307.3 = 483.1 pF. Note that the effective capacitance increases rapidly as the frequency approaches the self-resonant frequency. 2...
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This homework help was uploaded on 03/13/2014 for the course ECE 453 taught by Professor Staff during the Spring '08 term at University of Illinois, Urbana Champaign.

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