Thus we can calculate the gain using ms and ml or

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Unformatted text preview: S22 |2 − | S11 |2 − | D |2 C2 = S22 − DS1*1 We know that in this case, G = GT = GA = GA,max and this is the case for both 2-ports. Thus, we can calculate the gain using Γms and Γml , or simply G A,max = S 21 K − K 2 − 1 = 13.134 dB S12 ( ) Then Pout (dBm) = Pavo(1) (dBm) + GA,max (dB) = (Pavs(1) + GA,max) + GA,max = −10 + 2 × 13.134 = 16.27 (dBm) ∴ Pout (dBm) = 16.27 (dBm) (h) Terminate the output of the cascaded 2-port with Z0 and find Γin(1) . Γin ( 2 ) = S11 + Γin (1) = S11 + S12 S 21 ΓL = S11 = 0.35 1 − S 22 ΓL S12 S 21 Γin ( 2 ) 1 − S 22 Γin ( 2 ) = 0.35 + 0.127 = 0.477 ∴ S11 = Γin (1) = 0.477 [8-23] (a) Pout Pavs GT 3 dBm 8 dB 11 dBm (b) Pin 101.1 12.59 mW= 1.259 10-2 W Pout / G 11 dBm-10 dB= 1 dBm (c) Input M.F. =GT / G 8 10 P 'out Pout 2 dB Input M.F.=11 dBm+2 dB= 13 dBm (d) Output M.F. =GT / GA " P out 8 14 6 dB Pout Output M.F.=11 dBm+6 dB= 17 dBm Pout Input M.F. Output M.F.=11 dBm+2 dB+6dB= 19 dBm (e) Pout (f) "' 8-25 Solution a. Since the amplifier is conjugately matched when...
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This homework help was uploaded on 03/13/2014 for the course ECE 453 taught by Professor Staff during the Spring '08 term at University of Illinois, Urbana Champaign.

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