319 the corresponding input power is p1db 1 13192

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Unformatted text preview: pression occurs when: (1 − or 12 a ) = 10−1/20 16 |a| = 1.319. The corresponding input power is: P1dB = 1 1.3192 = 0.0174 W → 12.4 dBm. 2 50 b. Since there is no second-order nonlinearity in this device (k2 = 0), only first and third-order terms are present in the output: f1 , f2 , 3f1 , 3f2 , 2f2 + f1 , 2f1 + f2 , 2f2 − f1 , 2f1 − f2 c. In-band components are: 9 3 ￿ vo (t) = (k1 a + k3 a3 )(cos ω1 t +cos ω2 t)+ k3 a3 (cos(2ω2 − ω1 )t +cos(2ω1 − ω2 )t) 4 4 where k1 = 12 and k3 = −1. Gain compression can be ignored when 9 |k3 a3 | ￿ |k1 a| 4 or a2 ￿ 5.33. Assuming that gain compression can be ignored, then we want PIM = Pd 1 2326 2 k3 ( 4 ) a /50 122 2 k1 a /50 1 = 2 k3 ( 3 )2 a4 4 < 0.001 2 k1 which ensures that the intermodulation power is at least 30 dB below the power in the desired tones. This yields a2 ≤ 0.506. The corresponding input power constraint is Pin = 1 a2 ≤ 0.00506 W → 7.04 dBm. 2 50 2 [12-4 Solution] (a) The input power (Pin ) of each tone determines the relative magnitudes of the output power in each of the desired tones (Pd ) and the output power in each in-band third order intermodulation component (PI M ) through the following rel...
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