# Ifaresistorneedsto dissipate 486 watts ofpowerwhen9

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Unformatted text preview: r and the square of s. 36) Find the variation equation for the variation statement. 37) z varies jointly as y and the cube of x; z = 2688 when x = 4 and y = - 7 37) 38) The power that a resistor must dissipate is jointly proportional to the square of the current flowing through the resistor and the resistance of the resistor. If a resistor needs to dissipate 486 watts of power when 9 amperes of current is flowing through the resistor whose resistance is 6 ohms, find the power that a resistor needs to dissipate when 7 amperes of current are flowing through a resistor whose resistance is 8 ohms. 38) Solve. Write an equation to describe the variation. Use k for the constant of proportionality. 39) P varies directly as the square of R and inversely as S. 39) Find the variation equation for the variation statement. 40) t varies directly as r and inversely as s; t = 3 when r = 27 and s = 72 4 40) Answer Key Testname: MATH 096 PRACTICE EXAM III F08 1) x|x is a real number and x ≠ 7 4 2) - 4 3x 3) 5 4) 64 x - 1 5) 1 x + 5 6) x 7) 8) 1 sq in. 16y 4 7x2 9) 8x 10) 24x2 y 11) r(r + 1)(r + 1) 3m 2 - 20m + 14 12) (m - 1)(m - 6)(m - 4) 13) 3x - 2 x - 1 14) 8(y + 3) 3y 15) 3x + 2 9 - 4x 16) 9(y + 2) 5y 17) 5x + 7 25 - 49x 18) - 10xy + x2 5y 19) - 6 + 3 x4 20) 2x3 + 3x2 - 3 + 4 x2 + 7 6x3 21) - 6x + 5 22) 4x2 + x - 5 - 23) x - 3 + 5 4x - 1 2 x + 9 24) x2 - 2x + 4 25) 1 26) 22 27) ∅ 5 Answer Key Testname: MATH 096 PRACTICE EXAM III F08 28) t = A - P Pr 29) 51 doctors 7 30) 1 hours 8 1 31) 2 mph 2 32) y = 4x 33) 30 gallons 3 34) y = x 35) 56 meters per second per second 36) q = kr2 s2 37) y = - 6x3 y 38) 392 watts kR2 39) P = S 40) t = 8r s 6...
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## This document was uploaded on 03/09/2014 for the course MATH 096 at Western Nevada College.

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