problem21_82

University Physics with Modern Physics with Mastering Physics (11th Edition)

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Unformatted text preview: 21.82: First, the mass of the drop: -6 m) 3 3 4 (15.0 10 = 1.41 10 -11 kg. m = V = (1000 kg m ) 3 t = D v = 0.02 20 = 0.00100 s and the acceleration : Next, the time of flight: 1 2d 2(3.00 10 -4 m) 2 d = at 2 a = 2 = = 600 m s . 2 2 t (0.001 s) So: 2 (1.41 10 -11 kg )(600 m s ) a = F m = qE m q = ma E = = 1.06 10 -13 C. 4 8.00 10 N C ...
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