problem21_78

# University Physics with Modern Physics with Mastering Physics (11th Edition)

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• PresidentHackerCaribou10582
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21.78: a) 20.0 g carbon 67 . 1 mol g 0 . 12 0 . 20 = g mol carbon 0 . 10 ) 67 . 1 ( 6 = mol electrons C. 10 0.963 C) 10 60 . 1 ( ) 0 . 10 ( 6 19 A × = × = - N q This much charge is placed at the earth’s poles (negative at north, positive at south), leading to a force: N. 10 13 . 5 ) m 10 276 . 1 ( C) 10 963 . 0 ( 4 1 ) 2 ( 4 1 7 2 7 2 6 0 2 earth 2 0 × = × × = = πε R q πε F b) A positive charge at the equator of the same magnitude as above will feel a
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Unformatted text preview: force in the south-to-north direction, perpendicular to the earth’s surface: N. 10 44 . 1 m) 10 276 . 1 ( C) 10 963 . ( 2 4 4 1 2 45 sin ) 2 ( 4 1 2 8 2 7 2 6 2 earth 2 × = × × = ⇒ = πε F R q πε F...
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• NoProfessor
• Atom, Electric charge, mol Carbon, south-to-north direction

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