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Unformatted text preview: 001 x 10-4 M + 2 x 10-5 M) =
2 x 10-13 M2 s-1 / 1.201 x 10-4 M = 1.67 x 10-9 M s-1 = 1.67 nmole L-1 s-1
Question 3: You are studying another enzyme and you conduct an analysis of the effect of substrate concentration
on reaction velocity. At each substrate concentration, you initiate the reaction by adding the enzyme at the same final
concentration (0.01 nM), incubate for 5 min, and then measure the amount of product formed. You obtain the initial
velocity data shown in the table below. On the basis of these data, calculate Km, Vmax, kcat and the specificity
constant. [Hint: You should analyze these data graphically....
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- Fall '08