problem21_68

# University Physics with Modern Physics with Mastering Physics (11th Edition)

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21.68: a) j i F ˆ sin 4 1 ˆ cos 4 1 2 13 3 1 0 2 13 3 1 0 13 θ r q q πε θ r q q πε + + = j πε i πε ˆ 5 3 m) 10 16.0) ((9.00 nC) nC)(6.00 00 . 5 ( 4 1 ˆ 5 4 m) 10 16.0) ((9.00 nC) nC)(6.00 00 . 5 ( 4 1 4 0 4 0 13 - - × + + × + + = F . ˆ N) 10 (6.48 ˆ N) 10 64 . 8 ( 5 5 13 j i F - - × + × + = Similarly for the force from the other charge: j j j F ˆ ) 10 20 . 1 ( ˆ m) (0.0300 nC) nC)(6.00 00 . 2 ( 4 1 ˆ 4 1 4 2 0 2 23 3 2 0 23 N πε r q q πε - × - = - = - = Therefore the two force components are: N 10 64 . 8 5 - × = x F
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• English-language films, NC, 4 m, 10 m, Fy Fx, 0.0300 m

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