problem21_68

University Physics with Modern Physics with Mastering Physics (11th Edition)

  • Homework Help
  • PresidentHackerCaribou10582
  • 1

Info icon This preview shows page 1. Sign up to view the full content.

21.68: a) j i F ˆ sin 4 1 ˆ cos 4 1 2 13 3 1 0 2 13 3 1 0 13 θ r q q πε θ r q q πε + + = j πε i πε ˆ 5 3 m) 10 16.0) ((9.00 nC) nC)(6.00 00 . 5 ( 4 1 ˆ 5 4 m) 10 16.0) ((9.00 nC) nC)(6.00 00 . 5 ( 4 1 4 0 4 0 13 - - × + + × + + = F . ˆ N) 10 (6.48 ˆ N) 10 64 . 8 ( 5 5 13 j i F - - × + × + = Similarly for the force from the other charge: j j j F ˆ ) 10 20 . 1 ( ˆ m) (0.0300 nC) nC)(6.00 00 . 2 ( 4 1 ˆ 4 1 4 2 0 2 23 3 2 0 23 N πε r q q πε - × - = - = - = Therefore the two force components are: N 10 64 . 8 5 - × = x F
Image of page 1
This is the end of the preview. Sign up to access the rest of the document.
  • '
  • NoProfessor
  • English-language films, NC, 4 m, 10 m, Fy Fx, 0.0300 m

{[ snackBarMessage ]}

What students are saying

  • Left Quote Icon

    As a current student on this bumpy collegiate pathway, I stumbled upon Course Hero, where I can find study resources for nearly all my courses, get online help from tutors 24/7, and even share my old projects, papers, and lecture notes with other students.

    Student Picture

    Kiran Temple University Fox School of Business ‘17, Course Hero Intern

  • Left Quote Icon

    I cannot even describe how much Course Hero helped me this summer. It’s truly become something I can always rely on and help me. In the end, I was not only able to survive summer classes, but I was able to thrive thanks to Course Hero.

    Student Picture

    Dana University of Pennsylvania ‘17, Course Hero Intern

  • Left Quote Icon

    The ability to access any university’s resources through Course Hero proved invaluable in my case. I was behind on Tulane coursework and actually used UCLA’s materials to help me move forward and get everything together on time.

    Student Picture

    Jill Tulane University ‘16, Course Hero Intern