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resistor on the left.
Since the L acts like a wire, we have A3 = v(t->∞) = 0V.
Third, we find the initial values of energy variables: iL(0+) = iL(0–) and
vC(0+) = vC(0–). At t = 0–, we assume circuit values are constant, causing
the L to act like a wire and the C to act like an open circuit. The switch is
closed, connecting the parallel RLC to the voltage source and resistor on
The L, acting like a wire, shorts the 100 mΩ resistor and the open C.
Thus, the initial C voltage is zero:
vC(0+) = vC(0–) = 0V
Also, all the current will flow through the L and will be limited only by
the 1 kΩ resistor. iL (0+ ) = iL (0− ) = €...
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- Fall '08
- RLC, RC circuit, Voltage source, parallel rlc circuit