{[ promptMessage ]}

Bookmark it

{[ promptMessage ]}


Third we find the initial values of energy variables

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: urce and resistor on the left. Since the L acts like a wire, we have A3 = v(t->∞) = 0V. Third, we find the initial values of energy variables: iL(0+) = iL(0–) and vC(0+) = vC(0–). At t = 0–, we assume circuit values are constant, causing the L to act like a wire and the C to act like an open circuit. The switch is closed, connecting the parallel RLC to the voltage source and resistor on the left. The L, acting like a wire, shorts the 100 mΩ resistor and the open C. Thus, the initial C voltage is zero: vC(0+) = vC(0–) = 0V Also, all the current will flow through the L and will be limited only by the 1 kΩ resistor. iL (0+ ) = iL (0− ) = €...
View Full Document

{[ snackBarMessage ]}

Ask a homework question - tutors are online