problem21_64

# University Physics with Modern Physics with Mastering Physics (11th Edition)

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21.64: a) The magnitude of the field the due to each charge is , ) ) 2 ( 1 4 4 1 2 2 0 2 0 + = = x d πε q r q πε E where d is the distance between the two charges. The x -components of the forces due to the two charges are equal and oppositely directed and so cancel each other. The two fields have equal y -components, so: θ x d πε q E E y sin ) 2 ( 1 4 2 2 2 2 0 + = = where θ is the angle below the x -axis for both fields. ; ) 2 ( 2 sin 2 2 x
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Unformatted text preview: x d d θ + = thus 2 3 2 2 2 2 2 2 dipole ) ) 2 (( 4 ) 2 ( 2 ) 2 ( 1 4 2 x d πε qd x d d x d πε q E + = + + = The field is the y-directions. b) At large , ) 2 ( , 2 2 d x x so the relationship reduces to the approximations 3 dipole 4 x πε qd E ≈...
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• Sin, Electric charge, Field Island, equal y-components

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