M 340L HW 8 Solutions

E 75 correct the determinant of a can then be dened

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Unformatted text preview: j +k det[Ajk ] = (−1)j +k Mjk . 2. E = −75 correct The determinant of A can then be defined in terms of Co-factors by expanding either along a row as in 3. E = −73 4. E = −74 det[A] = aj 1 Cj 1 + aj 2 Cj 2 + . . . + ajn Cjn , 5. E = −71 or down a column as in Explanation: For a 2 × 2 determinant, det[A] = a1k C1k + a2k C2k + . . . + ank Cnk . ab = ad − bc . cd Consequently, the statement is TRUE . Thus E=2 4 41 −3 1 3 −3 −3 3 = 2(−12 − 3) − 3(12 + 3) . Consequently, 003 10.0 points The determinant of a triangular mat...
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This document was uploaded on 03/16/2014 for the course M 340L at University of Texas at Austin.

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