1-29 - parallel plate capacitor charged to an initial...

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Physics 1B Lecture 3A Wednesday, January 29 clicker and quiz scores posted on TED Physics 1B parallel plate capacitor, charged to an initial voltage difference. All wires and batteries are removed and the plates separation is doubled. C = 0 A d C 1 2 C Q Q Q = C V V 2 V | E | = V x | E | | E | U = Q 2 2 C U 2 U how must you physically set up the experiment so that ! V remains constant? Physics 1B 6 V 5μF 7μF 2μF 4μF 6 V C eq = 5 μ F + 7 μ F C eq = 2 μ F + 4 μ F 12μF 6μF 6 V 1 C eq = 1 12 μ F + 1 6 μ F 4μF Physics 1B 6 V 5μF 7μF 2μF 4μF 6 V 12μF 6μF 6 V 4μF Q = (4 μ F)(6 V) = 24 μ C V = 6 V 4μF: V = (24 μ C) / (12 μ F) = 2 V V = (24 μ C) / (6 μ F) = 4 V Q = 24 μ C Q = 24 μ C 12μF: 6μF: 5μF: 7μF: 2μF: 4μF: V = 2 V V = 2 V Q = (5 μ F)(2 V) = 10 μ C Q = (7 μ F)(2 V) = 14 μ C Q = (2 μ F)(4 V) = 8 μ C Q = (4 μ F)(4 V) = 16 μ C V = 4 V V = 4 V
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Physics 1B Quiz 2 is Friday ! You will need a scantron, a pencil, and a calculator !
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