Ch12_solutions

Ch12_solutions - and the moment of inertia would be I = MR...

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12-1) 12-2)
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12-3) a) For a fixed outside radius, R, the moment of inertia would be highest if all the mass were concentrated at the outside edges (as in a thin hoop). Conversely, for a fixed moment of inertia, we can reduce R as long as we can move enough mass to the outer edge. We can thus say that the merry-go-round would have a minimum outside radius if it were in the shape of a thin hoop,
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Unformatted text preview: and the moment of inertia would be I = MR 2 . The radius would then be 5 2 I 5.1 10 kg m R = = = 18 m M 1600 kg ! " . 12-4) But the pivot produces no torque around the center point so angular momentum is conserved around that point....
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Ch12_solutions - and the moment of inertia would be I = MR...

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