userdata-paziras-Chem51-HW_06ANS

# 0 go2 x 1 molo2 2molso2 x 0208molso2 320 go2 3 m olo2

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Unformatted text preview: the reaction was 93.7%, what is the theoretical yield of this reaction? Actual yield = 30.7 g Theoretical yield = ??? Percent yield = 93.7 Actual yield Theoretical yield Actual yield 30.7 g Theoretical yield = = = 32.8 g % yield 0.937 % yield = 5 13. How many grams o f SO2 can be produced from reaction of 10.0 g of H2S and 10.0 g of O2, as shown below: 2 H2S + 3 O2 ® 2 SO2 + 2 H2O Assume H2S is LR: 1 0.0 g H 2 S x 1 mol H 2 S 2 mol SO 2 x = 0.293 mol SO 2 34.1 g H 2 S 2 mol H 2 S Assume O2 is LR: 10.0 g O 2 x 1 mol O 2 2 mol SO 2 x = 0.208 mol SO 2 32.0 g O 2 3 m ol O 2 The second assumption is correct. Therefore, oxygen is the limiting reactant. 0.20 8 mol SO 2 x 64.1 g = 13.3 g SO 2 1 m o l 14. When 50.0 g of N2 is reacted with an excess of other reactants as shown below, 20.0 g of NaCN was produced. What is the percent yield of this react ion? Na2CO3 + 4 C + N2 ® 2 NaCN + 3 CO Calculate the theor...
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## This document was uploaded on 03/18/2014 for the course CHEM 51 at Los Angeles Mission College.

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