userdata-paziras-Chem51-HW_06ANS

250 go2 x 1 molo2 4molco2 x 0446m olco2 320 go2 7

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Unformatted text preview: below to answer the next 3 questions: 2 C2H6 (g) + 7 O2 (g) ® 4 CO2 (g) + 6 H2O (g) 8. How many mo les of water can be produced when 1.8 mo les o f C2H6 are used? 1.8 mol C2 H 6 x 6 mol H 2 O = 5.4 mol H 2 O 2 mol C2 H 6 9. How many mo les of CO2 are produced when 25.0 g of oxygen are consumed? 25.0 g O 2 x 1 mol O 2 4 mol CO 2 x = 0.446 m ol CO 2 32.0 g O 2 7 mol O 2 10. How many grams o f water is produced when 78.0 g of C2H6 are burned? 78.0 g C 2 H 6 x 1 mol C 2 H 6 6 mol H 2 O 18.0 g H 2 O x x = 140. g H 2 O 30.06 g C2 H 6 2 mol C 2 H 6 1 mol H 2 O 4 11. In the reaction shown below, if 10.0 g of CH4 is combined with 30.0 g of O2, what is maximum amount of CO2 that can be produced? CH4 (g) + 2 O2 (g) ® CO2 (g) + 2 H2O (g) Assume CH4 is LR: 10.0 g CH 4 x 1 mol CH 4 1 mol CO 2 x = 0.623 mol CO 2 16.04 g CH 4 1 mol CH 4 Assume O2 is LR: 30.0 g O 2 x 1 mol O 2 1 mol CO 2 x = 0.469 m ol CO 2 32.0 g O 2 2 mol O 2 The second assumption is correct. Therefore, oxygen is the limiting reactant 0.469 mol CO 2 x 44.0 g = 20.6 g CO 2 1 m o l 12. In an experiment with Zn and S, it was found that 30.7 g of ZnS was produced. If the percent yield of...
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This document was uploaded on 03/18/2014 for the course CHEM 51 at Los Angeles Mission College.

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