{[ promptMessage ]}

Bookmark it

{[ promptMessage ]}

userdata-paziras-Chem51-Chap_06

# Whatmassofoxygenwill

This preview shows page 1. Sign up to view the full content.

This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: and products in a balanced chemical equation. · A balanced chemical equat ion provides several important informat ion about the reactants and products in a chemical reaction. For example: 1N2(g) + 3 H2(g) 2 NH3(g) 1 molecule 3 molecules 100 molecules 300 molecules 1 million molecules 3 million molecules 1 mole N2 + 2 molecules 200 molecules 2 million molecules 3 moles H2 2 moles NH3 This is the MOLE RATIO between REACTANTS and PRODUCTS Summary of Stoichiometric Calculations in Chemistry Examples: 1. Determine each mo le ration based on the reaction shown below: 2 C4H10 + 13 O2 → 8 CO2 + 10 H2O a) mol O 2 = mol CO 2 b) 20 mol C 4 H 0 1 = mol H 2 O Chemistry 51 Chapter 6 STOICHIOMETRIC CALCULATIONS Mole­Mole Calculations: · Relates moles of reactants and products in a balanced chemical equat ion Examples: 1. How many mo les of nitrogen will react with 2.4 moles of hydrogen to produce ammo nia as shown in the reaction below? 1 N2(g) + 3 H2(g) 2 NH3(g) 1 mo l N2 2.4 mo l H2 x ¾¾¾¾ = 0.80 mol N2 3 mo l H2 Mole Ratio 2. How many mo les of ammo nia can be produced from 32 mo les of hydrogen? (Assume excess nitrogen present) 32 mo l H2 x ¾¾¾¾¾ = mo l NH3 3. In one experiment, 6.80 mol o f ammo nia are prepared. How many mo les of hydrogen were used up in this experiment? 21 Chemistry 51 Chapter 6 STOICHIOMETRIC CALCULATIONS Mass­Mole Calculations: · Relates moles and mass of reactants or products in a balanced chemical equation Examples: 1. How many grams o f ammo nia can be produced from the react ion of 1.8 mo les of nitrogen with excess hydrogen as shown below? 1 N2(g) + 3 H2(g) 2 NH3(g) 2 mo l NH3 17.0 g NH3 1.8 mo l N2 x ¾¾¾¾¾ x ¾¾¾¾¾ = 61 g NH3 1 mo l N2 1 mo l NH3 Mole Ratio Molar Mass 2. How many mo les of hydrogen gas are required to produce 75.0 g of ammo nia? 75.0 g NH3 x ¾¾¾¾¾¾¾ x ¾¾¾¾¾¾¾ = mol H2 3. How many mo les of ammo nia can be produced from the react ion of 125 g of nitrogen as shown above? 22 Chemistry 51 Chapter 6 STOICHIOMETRIC CALCULATIONS Mass...
View Full Document

{[ snackBarMessage ]}