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Unformatted text preview: L = 0, F R = Mg. Same reasons as above. Standing in the middle: F L = Mg/2, F R = Mg/2. Consider the torque about the middle of the board. The forces from the columns must then be equals, or else there would be a net torque about the middle of the board. Since they are equal, they must each support half the weight of the person. continued e) x = 0: R L F = Mg = 0 L F = Mg(1 - ) = Mg L x = L: R L L F = Mg = Mg L L F = Mg(1 - ) = 0 L x = L/2: R L L/2 F = Mg = Mg/2 L L/2 F = Mg(1 - ) = Mg/2 L...
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- Spring '08
- Force, 0 l, 2 L, 0 mg