002500230031 13x103m example2

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Unformatted text preview: reverse reaction be favored? (would reactants be favored?) · To answer this, a new quant it y is introduced: Qc = the Reaction Quotient = has the same form as Kc but the concentrations used to calculate its value are not equilibrium concentrations. Qc = [CH 4 ][H 2 O] (1.00x10­3 M)(1.00x10­3 M) = = 6.25 3 [CO][H 2 ] (2.00x10­2 M)(2.00x10­2 M) Kc = 3.92 Qc = 6.25 should decrease to · For the reaction mixture to reach equilibrium: Qc Qc decreases if: Ø Ø 3.92 [CH4], [H2O] decreases [CO], [H2] increases CO (g) + 3H2 (g) CH4 (g) + H2O(g) Ø The reaction goes to the left Ø Reverse react ion is favored Ø Formation of reactants is favored Qc = 0 Qc = ¥ K c Forward Rxn Reactants Reverse Rxn Equilibrium Increasing Qc 15 Products Chemistry 102 Chapter 14 PREDICTING THE DIRECTION OF REACTION · In General: For a reaction mixture that is NOT AT EQUILIBRIUM : aA + bB ¾¾ ® ¬¾ ¾ d [C]c [D] Qc = a b [A] [B] cC + dD Compare: Qc to Kc · If: Qc > K c ­ Reaction will go the left ( )...
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This document was uploaded on 03/18/2014 for the course CHEM 102 at Los Angeles Mission College.

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