Lechateliersprinciplestatesthat ifastress

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Unformatted text preview: l [N2] = [O2] = ¾¾¾¾ = 0.10625 M 8.00 L N2 (g) + ¾¾ ® O2 (g) ¬¾ 2 NO (g) ¾ Init ial 0.10625 0.10625 0 D –x –x +2x Equilibrium 0.10625–x 0.10625–x 2x K c = 0.0123 = 2 [NO]2 (2x) = [N 2 ][O 2 ] (0.10625 x)(0.10625 x) Taking square roots of both sides: Rearranging: Rearranging further: 2x (0.10625 x) 2x 0.106 25 x = = 18.03 x 0.1109 0.1109= 0.10625 = 19.03 x Equilibrium concentrations are: [O2] = [N2] = 0.10625 – x = 0.10625 – 0.005583 = 0.101 M [NO] = 2x = 2 x 5.583 x 10-3 M = 0.0112 M 18 x = 5.583 x 10 3 M Chemistry 102 Chapter 14 Example 4: Ammo nium hydrogen sulfide decomposes at room temperature as shown below: ¾¾ ® NH4HS (s) ¬¾ NH3 (g) + H2S (g) ¾ Kp= 0.108 at 25°C A sample of ammo nium hydrogen sulfide is placed in a flask at 25°C. After equilibrium has been reached, what is the total pressure of the flask? (Note: solids have no pressure) Kp = 0.108 = Example 5: At relat ively high temperatures, the following reaction can be used to produce methyl alcoho l: ¾¾ ® CO (g) + 2 H2 (g) ¬¾ CH3OH (l) ¾ Kc= 13.5 If the concentration of CO at equilibrium were found to be 0.010 M, what would be the equilibrium concentra...
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