userdata-paziras-Chem101-Chap_05A

Userdata-paziras-Chem101-Chap_05A

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Unformatted text preview: increases Volume must increase 298 K V2 = 5.83 L x ¾¾¾ = 6.36 L 273 K OR V1 T2 (5.83 L) (298 K) V2 = ¾¾¾ = ¾¾¾¾¾¾¾ = 6.36 L T1 (273 K) 2. A sample of nitrogen gas with a vo lume of 10.0 L has a temperature of –78°C. What is the vo lume of this gas at 25°C at constant pressure? 12 Chemistry 101 Chapter 5 Combined Gas Law · Boyle’s Law and Charles Law can be combined and expressed in a single statement. · The Volume of a gas: Boyle’s Law ­ is inversely proportional to its Pressure ­ is direct ly proportional to its Abso lute Temperature 1 V a ¾ P Charles’ Law · For a given amount of gas, this can be wr itten as a single equat ion: When temperature is constant: (T1 = T2 = T) T = ct P1V1 P2V2 ¾¾ = ¾¾ P1V1 ¾¾ = T1 P2V2 ¾¾ T2 T T P1V1 = P2V2 Boyle’s law When pressure is constant : P = ct T1 (P1 = P2 = P) P V1 P V2 ¾¾ = ¾¾ T2 V1 V2 ¾¾ = ¾¾ T1 T2 Charles’ Law Alternately: V2 = V1 x P1 T x 2 P2 T1 13 V a T Chemistry 101 Chapter 5 Examples: 1. A bacterial culture iso lated fro m sewage produced 41.3 mL o f methane gas (CH4) at 31 °C and 753 mm Hg pressure. What is the volume o f the methane gas at 0 °C and 760.0 mm Hg ? Initial V1 = 41.3 mL t...
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This document was uploaded on 03/18/2014 for the course CHEM 101 at Los Angeles Mission College.

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