Unformatted text preview: 1 = 31 °C T1 = 304 K P1 = 753 mm Hg Final V2 = ? t2 = 0 °C T2 = 273 K P2 = 760.0 mm Hg V2 = V1 x Temperature Ratio x Pressure Ratio T¯ V¯ V2 P- V¯ 273 K 753 mmHg = 41.3 mL x ¾¾¾ x ¾¾¾¾¾¾ = 36.7 mL 304 K 760.0 mm Hg OR P1 V1 T2 (753 mmHg) (41.3 mL)(273 K) V2 = ¾¾¾¾ = ¾¾¾¾¾¾¾¾¾¾¾¾¾ = 36.7 mL T1 P2 (304 K) (760.0 mm Hg) 2. The pressure of 1.50 L of a gas is doubled and its abso lute temperature is increased 3 times. What will the final vo lume of the gas be? 3. A sample of Cl2 occupies 8.50 L at 80 °C and 745 mmHg. What volume will it occupy at 30°C and 1.20 atm? 14 Chemistry 101 Chapter 5 RELATIONSHIP BETWEEN VOLUME AND AMOUNT OF GAS NOTE: · · Volume of gas is expressed in L or mL (V)
Amount of gas is expressed in number of mo les of gas (n) · Consider equal vo lumes of three different gases at the same temperature and pressure: 1 L He 1 L H2 1L O2 · Same Volume, Same temperature, Same Pressure
· Which cube contains the largest number of mo lecules ?
· The three cubes contain the same number of molecules! Reasons: 1. The vo lume of a gas is determined by the intermo lecular distances; Intermo lecular distances: depend on Volume and Pressure (the same) do not...
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- Fall '13
- Chemistry, mm Hg, vo lume