userdata-paziras-Chem101-Chap_05A

Initial p1 198atm v1 500l final p2 0974atm v2 p1

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Unformatted text preview: tm) 0.50 1/V (mL–1 ) 0.05 1.0 10. 1.0 0.10 2.0 5.0 2.0 0.20 V is inversely proportional to P 7 1/V is proportional to P Chemistry 101 Chapter 5 Examples: 1. A gas in a closed­tube mano meter has a measured pressure of 0.047 atm. Calculate the pressure in mm Hg. 760.0 mm Hg ? mm Hg = 0.047 atm x ¾¾¾¾¾¾ = 36 mm Hg 1.000 atm 0 2. You have a tank or argon gas at 19.8 atm pressure at 19 C. The vo lume of argon in the tank is 50.0 L. What would be the vo lume of this gas if you allowed it to expand to the pressure of the surrounding air (0.974 atm) ? Assume the temperature remains constant. Initial P1 = 19.8 atm V1 = 50.0 L Final P2 = 0.974 atm V2 = ? P1 V1 = P2V2 P1 V1 (19.8 atm) (50.0 L) V2 = ¾¾¾ = ¾¾¾¾¾¾¾¾ = 1020 L P2 (0.974 atm) 3. The pressure of a sample of gas with a volume o f 125 mL is decreased fro m 2.50 atm to 1.50 atm. What is the new vo lume? 8 Chemistry 101 Chapter 5 VOLUME­TEMPERATURE RELATIONSHIP FOR GASES · Gases contract when cooled and expand when heated · It fo llows: The Volume of a gas increases with temperature V(L) a = intercept 100 300 temperature (0 C) 200 · This is a linear relat ionship. The equation for a linear relationship is : y = a + b x V = a + b t volume intercept slope temperature...
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This document was uploaded on 03/18/2014 for the course CHEM 101 at Los Angeles Mission College.

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