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userdata-paziras-Chem101-Chap_05A

V1 t1 v2 t2 or v1 v2 t1 t2 orv2 v1 x t2 t1 examples 1

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Unformatted text preview: · To simplify the equat ion, the graph can be extrapolated to the temperature at which the vo lume of the gas beco mes 0. 9 Chemistry 101 Chapter 5 V(L) extrapolation a = intercept ­ 3000 C ­ 2000 C ­ 1000 C 0 + 1000 C 2000 C 3000 C ­ 2730 C 0 t = ­ 273 C Vgas = O V = a + bt becomes: 0 0 = a + (­273 C) b 273 b = a V = a + bt can now be rewritten: V = 273 b + bt = b (273 + t) = bT NOTE: at Absolute Temperature 10 Chemistry 101 Chapter 5 · A Plot Of Volume (V) as a function of Absolute Temperature (T) V(L) Absolute temperature (K) 0 K (­ 273 0 C) V = b T OR V ¾¾ = b = constant T 11 Chemistry 101 Chapter 5 CHARLES’ LAW · The relat ionship of temperature and volume in gases is called Charles’ Law. · The Volume occupied by a gas is directly proportional to the Absolute Temperature. V1 T1 ¾ = ¾ V2 T2 OR V1 V2 ¾ = ¾ T1 T2 OR V2 = V1 x ¾¾ T2 T1 Examples: 1. An experiment calls for 5.83 L of sulfur dioxide gas (SO2) at 0 °C and 1.00 atmospheres. What would be the vo lume of this gas at 25 °C and 1.00 atm ? (Note: the pressure does not change) Initial t1 = 0 °C T1 = 0 °C + 273 = 273 K V1 = 5.83 L Final t2 = 25 °C T2 = 25 °C + 273 = 298 K V2 = ? Temperature...
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