{[ promptMessage ]}

Bookmark it

{[ promptMessage ]}

userdata-paziras-Chem101-Chap_07A

097x107 2 n 1 1 m 1 2 n2 wheren1 andn2 areintegers n2

Info icon This preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: sio n spectrum of Hydrogen. · This equat ion is known as RYDBERG’S EQUATION: 1 1 1 7 ¾ = 1.097 x10 ( ¾ - ¾ ) m -1 2 2 l 2 n 1 ¾ = 0.25 2 2 n = an integer greater than 2 n = 3 l = 6.56 x 10 7 m = 656 nm Red Line n = 4 l = 4.86 x 10 7 m = 486 nm Blue­Green Line n = 5 l = 4.34 x 10 7 m = 434 nm Blue Line n = 6 l = 4.10 x 10 7 m = 410 nm Violet Line · Later Rydberg generalized his equation to include the wavelengths o f those spectral lines whose wavelengths are not in the range of visible light. GENERALIZED RYDBERG EQUATION: 1 1 = 1.097 x 107 ( 2 λ n 1 1 ) m 1 2 n 2 where: n1 and n2 are integers n2 > n1 Rydberg did not provide an actual explanation of the line spectra 7 Chemistry 101 Chapter 7 PLANCK’S QUANTIZATION OF ENERGY · Planck’s theory is based on experimental observat ions. Background: · THE LIGHT GIVEN OFF BY A HOT SOLID VARIES WITH TEMPERATURE At lower temperatures (750 °C) ­ red light is emitted (a heated solid glows red) At higher temperatures (1200 °C) ­ yellow and blue light is also emitted and mixes wit h the red light (the heated solid glows white) Planck’s Explanation: 1. The atoms of the so lid vibrate with a specific frequency which depends on the: ­ type of so lid, and ­ temperature of the solid 2. An atom could have only certain energies o f vibrat ion: where: E = nhn E = energy n = an integer, called quantum number (can be 1, 2, 3…) n = frequency of vibrat ion h = Planck’s constant = 6.63 x 10-34...
View Full Document

{[ snackBarMessage ]}

What students are saying

  • Left Quote Icon

    As a current student on this bumpy collegiate pathway, I stumbled upon Course Hero, where I can find study resources for nearly all my courses, get online help from tutors 24/7, and even share my old projects, papers, and lecture notes with other students.

    Student Picture

    Kiran Temple University Fox School of Business ‘17, Course Hero Intern

  • Left Quote Icon

    I cannot even describe how much Course Hero helped me this summer. It’s truly become something I can always rely on and help me. In the end, I was not only able to survive summer classes, but I was able to thrive thanks to Course Hero.

    Student Picture

    Dana University of Pennsylvania ‘17, Course Hero Intern

  • Left Quote Icon

    The ability to access any university’s resources through Course Hero proved invaluable in my case. I was behind on Tulane coursework and actually used UCLA’s materials to help me move forward and get everything together on time.

    Student Picture

    Jill Tulane University ‘16, Course Hero Intern