Lecture Notes 9

c o o co2

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Unformatted text preview: re for carbon disulfide CS2 Exercise: Write the Lewis structure for the carbonate ion CO3 2− A = 1 × 4 + 3 × 6 + 2 = 24 N = 4 × 8 = 32 O S = N − A = 32 − 24 = 8 =⇒ 4 bonds skeleton structure: O C O O O C ·· CO2 skeleton ·O· ·· . . . . . . . . . . . . . . . . O place the four bond pairs: ·· ·O · ·· ............. ............. C O ·· O ·· ............. ............. ............. ............. CO2 skeleton . . . . . . . . . . . . . . . . . O ............. ............. C ............. ............. ............. ............. O O CO2 L − 8 = leaves 24ewis 16 valence electrons: O . . . . . . . . . . . . . . . . ·O · ·· CO2 bonds · O · ·· ·O C · ·· ............. ............. C . . . . . . . . . . . . . . . . ............. ............. CO2 bonds CO2 Lewis GChem I 2− ............. ............. ............. ............. ............. ............. ............. ............. ·· O ·· 9.13 however: the double bond could also be placed between...
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