Lecture Notes 9

cl 8freon 12 bonds leaves

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Unformatted text preview: = N − A = 40 − 32 = 8 =⇒ 4 bond pairs skeleton structure: halogens are terminal; C is the central atom Cl F C F Cl Freon-12 skeleton place the 4 bond pairs GChem I 9.11 Cl . . . . . . . . . . . . . . . . F ............. ............. C ............. ............. F Cl Freon-12 skeleton Cl . . . . . . . . . . . . . . . . F ............. ............. C ............. ............. F . . . . . . . . . . . . . . . . . Cl 8Freon-12 bonds leaves 32 − 8 = 24 valence electrons electrons placed, C has octet; place 24 electrons as lone pairs on the halogens: ·· · Cl · ·· · ·· F · ·· . . . . . . . . . . . . . . . . ............. ............. C . . . . . . . . . . . . . . . . . ............. ............. ·· · F ·· · · Cl · · ·· · –Freon-12FoilTEX – Typeset by Lewis 1 calculate formal charges: 2 F : 7−6− = 0 2 2 Cl : 7 − 6 − = 0 2 8 C : 4−0− = 0 2 Exercise: Write the Lewis structure for methanol CH3 OH GChem I 9.12 Exercise: Write the Lewis structu...
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This document was uploaded on 03/18/2014 for the course CHEM 1303 at SMU.

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