Lecture Notes 9

o resonance formal charges 8 c 40 0 2 4 o

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Unformatted text preview: the central C atom any of the other two O atoms: ·· ·O · ·· 2− ·· ·O· ·· . . . . . . . . . . . . . . . . ............. ............. C ............. ............. ............. ............. ·· O ·· ↔ · O ·· ↔ ·· ·O · ·· . . . . . . . . . . . . . . . . . C ·O· ·· . . . . . . . . . . . . . . . . ............. ............. . . . . . . . . . . . . . . . . C ............. ............. ·· O· ·· · ↔ 2− ·· ·O· ·· ............. ............. ............. ............. 2− ............. ............. ·· · O· ·· resonance formal charges: 8 C : 4−0− = 0 2 4 O : 6−4− = 0 2 2 O : 6 − 6 − = −1 2 Exercise: Write the Lewis structure for phosphorus pentafluoride GChem I – Typeset by FoilTEX – 9.14 3 PF5 A = 1 × 5 + 5 × 7 = 40 N = 6 × 8 = 48 S = N − A = 48 − 40 = 8 =⇒ 4 bonds skeleton structure: F F F F P F P F FF F F ?only four bonds? need at least five increase S to 10; leaves 30 electrons for lone pairs F F F ....
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This document was uploaded on 03/18/2014 for the course CHEM 1303 at SMU.

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