Lecture Notes 9

p 34

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Unformatted text preview: ...... ............. . . . . . . . . . . . . . . . . . H H C . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . C H . . . . . . . . . . . . . . . . . H example 2: P2 O7 4− A = 2 × 5 + 7 × 6 + 4 = 56 N = 2 × 8 + 7 × 8 = 72 S = N − A = 72 − 56 = 16 =⇒ 8 bonds skeleton structure: – Typeset by FoilTEX – 1 GChem I – Typeset by FoilTEX – 9.21 1 O O 4− O P O O P O O place the eight bond pairs, then fulfill octet rule, then check if all electrons are accounted for: ·· ·O · ·· ·· ·O· ·· . . . . . . . . . . . . . . . . ............. ............. P . . . . . . . . . . . . . . . . . ·O· · ·· · 4− ·· ·O· ·· ............. ............. ·· O ·· . . . . . . . . . . . . . . . . ............. ............. P . . . . . . . . . . . . . . . . . ·O· · ·· · ............. ............. ·· O· ·· · 8 bond pairs + 20 lone pairs = 56 electrons the bonds between the P’s and the terminal O’s are coordinate covalent bonds GChem I – Typeset by FoilTEX – 9.22 2 formal charges: 8 P : 5−0− = 1 2 2 terminal O : 6 − 6 − = −1 2 formal charges sum to 4− cons...
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