Unformatted text preview: , we consider approximations of the form U (x) =
Let's examine this result more closely. N1
X
; j =1 cj j (x): (1.3.5) 10 Introduction
U(x) cj cj1 cj+1 φj1 (x) 1 φj (x) x
x0 xj1 xj xj+1 xN Figure 1.3.2: Piecewise linear nite element solution U (x).
1. Since each j (x) is a continuous piecewise linear function of x, their summation
U is also continuous and piecewise linear. Evaluating U at a node xk of the mesh
using (1.3.4b) yields U (xk ) = N1
X
; j =1 cj j (xk ) = ck : Thus, the coe cients ck , k = 1 2 : : : N ; 1, are the values of U at the interior
nodes of the mesh (Figure 1.3.2).
2. By selecting the lower and upper summation indices as 1 and N ; 1 we have ensured
that (1.3.5) satis es the prescribed boundary conditions U (0) = U (1) = 0:
As an alternative, we could have added basis elements
approximation and written the nite element solution as U (x) = N
X
j =0 0 (x) and cj j (x): N (x) to the
(1.3.6) Since, using (1.3.4b), U (x0 ) = c0 and U (xN ) = cN , the boundary conditions are
satis ed by requiring c0 =...
View
Full Document
 Spring '14
 JosephE.Flaherty
 Numerical Analysis, Finite Element Method, Boundary value problem, Cj J, nite element

Click to edit the document details