problem21_32

# University Physics with Modern Physics with Mastering Physics (11th Edition)

• Homework Help
• PresidentHackerCaribou10582
• 1

This preview shows page 1. Sign up to view the full content.

21.32: a) ( 29 j j E ˆ ) C N 10 813 . 2 ( m 0400 . 0 C) 10 00 . 5 ( ) C m N 10 9 ( ˆ 4 4 2 9 2 2 9 2 1 0 1 1 × - = × - × = = - r πε q ( 29 C N 10 08 . 1 m) 0400 . 0 ( 0.0300m C) 10 00 . 3 ( ) C m N 10 9 ( 4 2 2 9 2 2 9 2 2 2 2 × = + × × = = - r q E The angle of , 2 E measured from the axis, - x is ( 29 ° = - - 9 . 126 tan 180 cm 3.00 cm 00 . 4 1 Thus j i j i E ˆ ) C N 10 (8.64 ˆ ) C N 10 6.485 ( ) 9 . 126 sin ˆ 9 . 126 cos ˆ ( ) C N 10 080 . 1 ( 3 3 4 2 × + × - = ° + ° × = b) The resultant field is
This is the end of the preview. Sign up to access the rest of the document.
• '
• NoProfessor

{[ snackBarMessage ]}

### What students are saying

• As a current student on this bumpy collegiate pathway, I stumbled upon Course Hero, where I can find study resources for nearly all my courses, get online help from tutors 24/7, and even share my old projects, papers, and lecture notes with other students.

Kiran Temple University Fox School of Business ‘17, Course Hero Intern

• I cannot even describe how much Course Hero helped me this summer. It’s truly become something I can always rely on and help me. In the end, I was not only able to survive summer classes, but I was able to thrive thanks to Course Hero.

Dana University of Pennsylvania ‘17, Course Hero Intern

• The ability to access any university’s resources through Course Hero proved invaluable in my case. I was behind on Tulane coursework and actually used UCLA’s materials to help me move forward and get everything together on time.

Jill Tulane University ‘16, Course Hero Intern