05268 a 1 0 rc 1 rd rd e1 e2 e3 rd rd e1 e2 0 e3 rc

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Unformatted text preview: =0−1 Correct answer: 1.05268 A. 1 0 RC −1 RD RD E1 + E2 E3 RD RD E1 + E2 0 E3 RC = − [(E1 + E2 ) RD − E3 RD ] − [RC (E1 + E2 ) − 0] = RD (E 3 − E 1 − E 2 ) − RC (E 1 + E 2 ) = (8.6 Ω) (3.7 V − 9.2 V − 1.8 V) −(7.3 Ω) (9.2 V + 1.8 V) = −143.08 V Ω . Explanation: + (−1) RD I3 E3 RC I2 RB and Using determinants, 10.0 points I3 1 E2 RA E1 I1 At a junction (Conservation of Charge) I1 + I2 − I3 = 0 . Expanding along the first column, the denominator is (1) Kirchhoff’s law on the...
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This document was uploaded on 03/19/2014 for the course PHY 316L at University of Texas at Austin.

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