The currents are owing in the direction indicated by

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Unformatted text preview: (58945) 2 Then, for the upper circuit 002 10.0 points In this problem assume that the batteries have zero internal resistance. The currents are flowing in the direction indicated by the arrows. 8. 2 V 9. 2 Ω I1 I2 E 1 − I2 R 2 − I1 R 1 = 0 (3) E1 + E2 E 1 + E 2 − I 1 R 1 = 0I 1 = R1 8.2 V + 20 V = 9. 2 Ω = 3.06522 A . Alternate Method: Using the outside loop 24.1 Ω −E1 − E2 + I1 R1 = 0 E1 + E2 I1 = . R1 20 V I3 Find the current through the 9.2 Ω resistor and the 8.2 V battery...
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This document was uploaded on 03/19/2014 for the course PHY 316L at University of Texas.

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