problem21_16

# University Physics with Modern Physics with Mastering Physics (11th Edition)

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21.16: ( 29 N 100 . 0 m 60 . 0 C) 10 0 . 2 ( C) 10 . 20 ( ) C m N 10 9 ( 2 6 6 2 2 9 21 = × × × = - - F 1 Q F is equal and opposite to Q F 1 (Ex. 21.4), so ( 29 ( 29 N 17 . 0 N 23 . 0 1 1 = - = y Q x Q F F Overall: N 27 . 0 N 17 . 0 N 100 . 0 N 23 . 0 = + = - = y x F F The magnitude of the total force is ( 29 ( 29 N. 35 . 0 N 27 . 0 N 23 . 0 2 2
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Unformatted text preview: The direction of the force, as measured from the + y axis is 40 27 . 23 . tan 1 = =-θ...
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