At 650 k the value of the equilibrium constant kp for

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Unformatted text preview: ___Sp 14__________ 8. At 650 K, the value of the equilibrium constant Kp for the synthesis of ammonia is 4.3 x 10-4. If a reaction vessel contains an initial mixture of [N2] = 0.010 M, [H2] = 0.030 M, and [NH3] = 0.0002 M, will more ammonia form? (10 pts) N2(g) + 3H2(g) ⇄ 2NH3(g) 4 moles 2 moles Δn Kp = Kc(0.0821•T) Solve for Kc: Kc = 1.22 Solve for the Reaction Quotient: Qc < Kc Hence, the mixture will form ammonia because the reaction moves in the direction of the products. 9. The value of Kc for the thermal decomposition of hydrogen sulfide is 2.2 x 10-4 at 1400 K. A sample of gas with the initial concentration of H2S is 6.00 M is heated to 1400 K in a sealed vessel. Calculate the equilibrium concentration of H2S in moles per liter. Assume the initial concentrations of the products to be ze...
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This document was uploaded on 03/19/2014 for the course CHEMISTRY 102 at Los Angeles Harbor College.

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