15 0 0 c x x x e 015 x x x poh log803 x 10 6

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Unformatted text preview: + OHI 0.15 --0 0 C -x --+x +x E 0.15 – x --x x pOH = -log(8.03 x 10-6) = 5.10 pH = 14 – 5.10 = 8.90 3. Calculate the pH of a 0.25 M C5H5NHCl salt solution. (10 pts) Kb =1.7 x 10-9 for C5H5N C5H5NH ⇄ C5H5N + H+ I 0.25 --0 0 C -x --+x +x E 0.25 – x --x x pH = -log(1.21 x 10-3) = 2.92 Chemistry 102 Exam 2 Name _____Mr. Perfect_____________________________________ Date ______F 13_____________ 4. Carbonic acid (H2CO3) is used to buffer blood. Use the Henderson-Hasselbalch equation to calculate the ratio of HCO3- to H2CO3 in blood h...
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