75 x 10 3 mol 750 x 10 4 mol hcl remains ph log107 x

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Unformatted text preview: -3 mol acid 4.50 x 10-3 – 3.75 x 10-3 mol = 7.50 x 10-4 mol HCl remains pH = -log(1.07 x 10-2) = 1.97 Chemistry 102 Exam 2 Name _____Mr. Perfect_____________________________________ Date ______F 13_____________ 8. Complete the following table. (10 pts) [H+] 3.46 x 10-4 [OH-] 2.88 x 10-11 pH 3.46 Acid or Base? acid 1.49 x 10-11 6.7 x 10-4 10.8 base 6.31 x 10-11 1.58 x 10-4 10.2 base 7.2 x 10-9 1.39 x 10-6 8.14 base 9. Which of the following indicators would be appropriate for a titration with an equivalence poin...
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This document was uploaded on 03/19/2014 for the course CHEMISTRY 102 at Los Angeles Harbor College.

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