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384 256 56 9 21 2 8 57 256 to find

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Unformatted text preview: ment of the square root must be positive (the alternative is an imaginary energy), meaning the minimum energy is the result of subtracting the second term from the first. = 384ℏ 256 + 56 − 9 ℏ + 21 2 8 ℏ 57 + 256 / To find the coefficients corresponding to this solution, one can begin with one of the secular equations: − − + − =0 → =− − ℏ + − 8 2 ℏ 2 32 =− = + − = 2 32 2 8 The trial wavefunction must be normalized: 1= = = = = = (Whew!) + + +2 + 1 1+ = = + = 1+ 8 + 2 = 8 2 = 1+ ℏ + 2 32 ℏ + 2 32 − 1 +2 0+ 1 / − 1+ 8 2 ℏ + 2 32 / −...
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This document was uploaded on 03/18/2014 for the course CHEM 372 at Gustavus.

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