Unformatted text preview: ment of the square root must be positive
(the alternative is an imaginary energy), meaning the minimum energy is the result of subtracting
the second term from the first.
= 384ℏ 256 + 56 − 9 ℏ + 21 2 8 ℏ 57
+ 256 / To find the coefficients corresponding to this solution, one can begin with one of the secular
equations:
−
−
+
−
=0 →
=−
−
ℏ
+
−
8
2
ℏ
2
32
=−
=
+
−
=
2
32
2
8
The trial wavefunction must be normalized:
1= =
=
= = =
(Whew!) + + +2
+
1 1+
= = + = 1+
8 + 2 =
8 2 = 1+
ℏ
+
2
32 ℏ
+
2
32 − 1 +2 0+ 1 / − 1+ 8 2 ℏ
+
2
32 / −...
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 Spring '14
 SteveMiller
 Physical chemistry, Atom, pH, Conservation Of Energy, Energy, Characteristic polynomial, trial wavefunction

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