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Its a weird looking coordinate system but it makes

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Unformatted text preview: s the integral a bit easier to evaluate and gives the same answer.) A) B) C) D) E) kq L / 2 dx L / 2 d L / 2 x L 2kq L / 2 dx L 0 d x kq L / 2 dx L L / 2 x d kq L dx 0 d L / 2 x L kq L dx L 0 x d V V V V V Version 1 Page 8 13. Charge is distributed on the surface of two very large insulating slabs such that σ1=σ3=σ4=σ and σ2=-σ. What is the electric field at point C? To keep proper track of signs I follow this procedure: 1) draw E-field arrow for each sheet at point C without considering the sign of the sheet (I treat them all positive). 2) write an equation for E at point C. Arrows that point left get a negative sign. 3) plug in the actual value of charge density for each sheet (including the sign this time). This way I count sign from charge only once. A) 0 B) E 2 0 C) 3 E 2 0 D) 3 E 2 0 E) E 2 0 Version 1 Page 9 14. Approximately what is the electric field at point P given that x>>d? The x components cancel. We need to find the y component. Due to symmetry we can find y component of field from posit...
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