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6. This is a closed book, 90 minute exam. Turn off and put away all electronic
devices. You may use a calculator and one 3”x5” note card or equivalent.
k = 1/4πε0 =9x109 Nm2/C2
e = 1.6x1019 C
μ = micro =106 ε0 = 8.85x1012 C2/Nm2
1 eV= 1.6x1019 J
g = 9.8 m/s2 me = 9.1 x 1031 kg MP=1.67 x 1027 kg Version 1 Page 1 1. A large ring with charge Q uniformly distributed around it and with radius 2R is
positioned so that its axis coincides with the axis of a smaller ring of uniform charge q and
radius R. A point on the axis is a distance R from the smaller ring and 2R from the larger
ring as shown. What must Q be such that the electric potential at the point due to the two
rings is zero? (Take the reference V = 0 to be at infinite separation.) Q
q
2R
R
R A)
B)
C)
D)
E) 2R 4q
2q
+2q
+q/2
+4q 2. In a certain region of space the electric potential increases linearly with x, where x is the
distance traveled to the east. Th...
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This test prep was uploaded on 03/22/2014 for the course PHYSICS 240 taught by Professor Davewinn during the Spring '08 term at University of Michigan.
 Spring '08
 DaveWinn
 Physics

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