Practice 4 Solutions

3 1 0 1 0 1 1 1 2 110 1 1 1 2 1 1 0 a 0 1 1

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Unformatted text preview: 5] Find eAt where A is the matrix 2 0 −1 1 A= 0 2 −1 1 1 3 × 3 Exercise Set K (symmetric matrices), November , λ = 0, 2, 3 eAt 1 −1 2 110 1 −1 −1 2t 3t 1 e e 1 −2 + 1 1 0 + −1 1 1 = −1 6 2 3 2 −2 4 000 −1 1 1 [6] Find eAt where A is the matrix −2 1 −1 0 A = 1 −3 −1 0 −3 1 −1 1 000 4 2 −2 −3t −t e e −1 0 1 1 + e 2 1 −1 + 1 −1 = 3 2 6 1 −1 1 011 −2 −1 1 −4t λ = −4, −3, −1 eAt [7] Find eAt where A is the matrix 111 A = 1 2 0 102 λ = 0, 2, 3 eAt 4 −2 −2 0 0 0 111 2t 3t e e 1 1 1 + 0 1 −1 + 1 1 1 = −2 6 2 3 −2 1 1 0 −1 1 111 [8] Find eAt where A is the matrix −2 0 1 1 A = 0 −2 1 1 −3 1 1 −2 1 −1 0 111 −2t −t e e e 1 −1 1 −2 + 1 0 + 1 1 1 = 6 2 3 −2 −2 4 0 00 111 −4t λ = −4, −2, −1 eA...
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