Practice 4 Solutions

# 2 001 12 0 eat 7 find eat where a is the matrix 3 2 2

This preview shows page 1. Sign up to view the full content.

This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: 1 2 λ = 1, 1, 1 3 −3 3 100 −2 21 n(n − 1) 3 −3 3 1 2 + = 0 1 0 + n −1 2 0 00 001 1 −1 1 An [8] Find An where A is the matrix 2 −2 −1 2 −1 A= 2 −2 −2 2 , 3 × 3 Exercise Set G (identical roots), November λ = 2, 2, 2 −2 2 2 100 0 −2 −1 n−2 n(n − 1) 2 2 −2 −2 0 −1 + = 2n 0 1 0 + n 2n−1 2 2 −4 4 4 001 −2 −2 0 An , 3 × 3 Exercise Set H (identical roots), November 3 × 3 Exercise Set H (identical roots) Linear Algebra, Dave Bayer, November , [1] Find eAt where A is the matrix 23 3 A = 1 1 −1 −1 1 3 λ = 2, 2, 2 0 0 0 100 0 3 3 2 2t te 0 3 3 = e2t 0 1 0 + te2t 1 −1 −1 + 2 0 −3 −3 001 −1 1 1 eAt [2] Find eAt where A is the matrix −2 22 1 3 A = −1 1 −1 1 λ = 0, 0, 0 4 −4 4 100 −2 22 2 t 4 −4 4 1 3 + = 0 1 0 + t −1 2 0 00 001 1 −1 1 eAt [3] Find eAt where A is the matrix −1 3 2 A = 2 1 −2 −2 3 3 λ = 1, 1, 1 100 −2 3 2 6 0 −6 2t te 00 0 = et 0 1 0 + tet 2 0 −2 + 2 6 0 −6 001 −2 3 2 eAt [4] Find eAt where A is the matrix −2 2 2 1 A = 1 −2 −2 2 −2 λ = −2, −2, −2 , 3 × 3 Exercise Set H (identical roots), November −2 4 2 100 022 2 −2t te −2 4 2 = e−2t 0 1 0 + te−2t 1 0 1 + 2 2 −4 −2 001 −2 2 0 eAt [5] Find eAt where A is the matrix −2 −1 1 A = −1 −2 3 −1 −1 1 λ = −1, −1, −1 eAt 1 1 −2 100 −1 −1 1 2 −t te −1 −1 2 = e−t 0 1 0 + te−t −1 −1 3 + 2 0 0 0 001 −1 −1 2 [6] Find eAt where A is the matrix 22 2 A = 1 2...
View Full Document

Ask a homework question - tutors are online