enee204Lecture_18_Gomez

Enee204Lecture_18_Go - Lecture 18 Chap 8 Dependent Sources How to solve circuits with sources that depend on other circuit parameters(Nodal and

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Lecture 20 1 Welcome to ENEE 204 Basic Circuit Theory Lecture 18 Chap. 8 Dependent Sources - How to solve circuits with sources that depend on other circuit parameters (Nodal and Mesh Analysis) - BJT Transistor - Amplifiers - BJT as Amplifier -Op-ampc
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Lecture 20 2 New topic: dependent sources Independent sources + Dependent sources +
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Lecture 20 3 There are four types of dependent sources A i x i x Current controlled currrent source + v x Gv x Voltage controlled current source + R i x i x Current controlled voltage source + + v x Av x Voltage controlled voltage source
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Lecture 20 4 Simple examples + s V ) R )(R R (R R R out v 4 3 2 1 4 2 100 + + = + v 2 A i 2 A=5 R 2 R 1 R 3 R 4 + v s i 2 s V ) R (R R out v 2 1 4 5 + = + + v 2 A v 2 A=100 R 2 R 1 R 3 R 4 v s vcvs cccs
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Lecture 20 5 For more complex circuits we can use nodal analysis (mainly current sources) Y 3 I s3 = G 3 v 1 Y 2 I s1 I s2 = G 2 v 2 Y 1 + v 2 + v 1 v 1 v 3 v 2 i 3 =? + = + + s3 s2 s2 s1 2 1 3 2 3 3 3 1 I ˆ - I ˆ - I ˆ I ˆ Y Y Y Y Y v v Y I s2 = G 2 v 2 = G 2 v 2 I s3 = G 3 v 1 = G 3 v 1 ^ ^ = + + + + 0 I ˆ G Y Y G Y G Y Y Y s1 2 1 2 3 2 3 3 2 3 3 1 v v I 3 =Y 3 ( v 1 - v 2 ) ^
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Lecture 20 6 Circuits with mainly voltage sources are easier to solve using mesh analysis Z 3 V s1 Z 2 V s2 = A v 2 V s3 = R I 3 Z 1 + v 2 + v 1 + + + I 1 I 2 = + + + s3 s2 s1 2 1 4 3 3 3 3 2 1 V ˆ - V ˆ V ˆ Z Z Z Z Z Z Z I I Z 4 V s2 = A Z 2 I 1 V s3 = R ( I 1 -I 2 ) = + + + + + 0 V ˆ R Z Z R Z Z AZ Z Z Z s1 2 1 4 3 3 3 2 3 2 1 I I
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Lecture 20 7 Thevenin and Norton equivalents can be used for networks containing dependent sources: + + v 2 100 v 2 R 2 R 1 R 3 R 4 v s A B Simple example: s OC v ) R )(R R (R R R v 4 3 2 1 4 2 100 + + = R R R R sc I oc V Th Z 4 3 4 3 + = = + - Z Th V OC A B 3 2 1 2 3 2 100 100 R R R v R R v I s SC + = =
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Lecture 20 8 Another example: Thevenin Equivalent 2 1 2 99 R R v R V s OC = + v 2 100 v 2 R 1 R 2 v s A B + 2 99 1 R R s v i = KVL: s v R R i s v iR iR iR = = + ) 2 99 1 ( 0 2 2 100 1 First find V oc .
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This note was uploaded on 04/07/2008 for the course ENEE 204 taught by Professor Gomez during the Fall '04 term at Maryland.

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Enee204Lecture_18_Go - Lecture 18 Chap 8 Dependent Sources How to solve circuits with sources that depend on other circuit parameters(Nodal and

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