problem20_46

University Physics with Modern Physics with Mastering Physics (11th Edition)

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20.46: a) 00 . 2 1 2 = = p p atm, L, 00 . 6 L. 6.00 L)(3/2) 00 . 4 ( 2 3 1 2 1 2 = = = = = V V V V T T 111 . 1 ) 9 / 5 ( 2 2 3 2 3 = = = p p p T T atm, 67 . 1 ) 2 / 3 ( 3 3 4 4 3 = = = p p p V V atm. As a check, 00 . 2 ) 5 / 6 ( 4 4 1 4 1 = = = p p p T T atm. To summarize, = ) , ( 1 1 V p (2.00 atm, 4.00 L) = ) , ( 2 2 V p (2.00 atm, 6.00 L) = ) , ( 3 3 V p (1.111 atm, 6.00 L) = ) , ( 4 4 V p (1.67 atm, 4.00 L). b) The number of moles of oxygen is , 1 1 1 RT V p n = and the heat capacities are those in Table (19.1). The product J; 4 . 810 value the has 1 1 = x V p using this and the ideal gas law, J, 1422 2) 1 J)( 4 . 810 )( 508 . 3 ( 1 : i 1 2 = = - = = T T x R C T nC Q P P J. 405 2) 1 J)( 4 . 810 ( 1 1 2 1 = = - = = T T x V p W 0. W J, 1355 3) 2 J)( 4 . 810 )( 508 . 2 ( : ii 1 2 3 = - = - = - = = T T T x R C T nC Q V V W Q V V T T x V V nRT W = - = = = = J, 274 3) 2 ( ln 6) 5 J)( 4 . 810 ( ln ln : iii 3 4 1 3 3 4 3 0. W J, 339 6) 1 J)( 4 . 810 )( 508 . 2 ( 1 : iv 1 4 = = =
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Unformatted text preview: -= ∆ = T T x R C T nC Q V V In the above, the terms are given to nearest integer number of joules to reduce roundoff error. c) The net work done in the cycle is J. 131 J 274-J 405 = d) Heat is added in steps i and iv, and the added heat is J 1761 J 339 J 1422 = + and the efficiency is 7.5%. or , 075 . J 1761 J 131 = The efficiency of a Carnot-cycle engine operating between %. 44 44 . 1 is K 450 and K 250 450 250 = =-...
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  • 7.5%, 44%, 250 K, 274 J, 339 J

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