PSY201 9.30.13 To Post

25 raw 094 4 using the normal curve table determine

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Unformatted text preview: ff: Z = 0.25 Z = 0.25, Raw = 0.94 4.  Using the normal curve table, determine the probability (percentage) of geeng a score more extreme than that Z ­score [in the direcDon you care about!] Remember how to do this?? Back to using our normal curve table to calculate the percentage in part of the curve! Do we want to find % Mean to Z, or % in tail? 0.58 0.74 0.9 1.06 1.22 .94 [email protected] 1: Dis of means Predicted Mean: μM = .90 Standard [email protected]: σM = 0.16 Z score cutoff: Z = 0.25 Z = 0.25, Raw = 0.94 4.  Using the normal curve table, determine the probability (percentage) of geeng a score more extreme than that Z ­score [in the direcDon you care about!] Remember how to do this?? Back to using our normal curve table to calculate the percentage in part of the curve! Do we want to find % Mean to Z, or % in tail? And we will need to add + 50% 0.58 0.74 0.9 1.06 1.22 .94 [email protected] 1: Dis of means Predicted Mean: μM = .90 Standard [email protected]: σM = 0.16 Z score cutoff: Z = 0.25 Z = 0.25, Raw = 0.94 4.  Using the normal curve table, determine the probability (percentage) of geeng a score more extreme than that Z ­score [in the direcDon you care about!] First, let’s [email protected] should be between 50% and 84% Second, look up Z = .25 on normal curve table… corresponds to 9.87% (in the Mean to Z column) Third, add 50% (bo\om half of curve): 50% + 9.87% = 59.87% 12 9/29/13 0.58 0.74 0.9 1.06 1.22 .94 Shaded region is power Z = 0.25, Raw = 0.94 4.  Using the normal curve table, determine the probability (percentage) of geeng a score more extreme than that...
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This note was uploaded on 03/24/2014 for the course PSY 21201 taught by Professor Bernard during the Winter '13 term at SUNY Stony Brook.

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