problem20_32

University Physics with Modern Physics with Mastering Physics (11th Edition)

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20.32: a) The final temperature, found using the methods of Chapter 17, is C, 94 . 28 K) kg J kg)(4190 (0.800 K) kg J kg)(390 50 . 3 ( ) C K)(100 kg J kg)(390 50 . 3 ( ° = + ° = T or C 9 . 28 ° to three figures. b) Using the result of Example 20.10, the total change in entropy is (making the conversion to Kelvin temperature) K. J 2 . 49 K 273.15 K 302.09 ln K) kg J kg)(4190 800 . 0 ( K 373.15
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Unformatted text preview: K 302.09 ln K) kg J kg)(390 50 . 3 ( = + = S (This result was obtained by keeping even more figures in the intermediate calculation. Rounding the Kelvin temperature to the nearest K 01 . gives the same result....
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This document was uploaded on 02/06/2008.

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