Unformatted text preview: e same position. So the graph should not have both x > 0 and x < 0. That rules out the last 3 options above (3 5). Since the car accelerates and decelerates, the velocity, dx/dt, is not constant over the entire trip. That rules out (2), leaving just (1). Problem 8 One object is shot vertically upwards with an initial velocity of 100 m/s. Another object is shot vertically upwards with a velocity of 10 m/s. The first object climbs to a maximum height that is Q times the maximum height of the second object. Q is: (1) 100 (2) 10 (3) 33.3 (4) 3.3 (5) 1000 Use v 2 = v 2 + 2a ( y − yo ) with y = 0 at launch (yo = 0), a = –g then y = ymax at the o
top of the trajectory where v = 0. Then 0 = v 2 − 2g( ymax − 0) , which...
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This document was uploaded on 03/24/2014.
 Spring '14
 Physics

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