For that car the kinematic equation becomes x p 0 pt

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Unformatted text preview: (4) 1.1 m/s2 (5) 6.1 m/s2 Use the kinematic equation: x = x o + v o t + 1 at 2 . Placing the car at the origin of 2 the x axis at t = 0 (when it starts accelerating) makes xo = 0 and since it starts from rest, vo = 0. Solving what’s left for the acceleration gives: 1 x = at 2 2 2x 80 m ⇒ a = 2 = 2 2 2 = 5, 3.2, 2.2 s2 t (4 ,5 ,6 ) Problem 6 Two automobiles are a distance d = 200 km apart (or 250km, or 300 km) and traveling toward each other with one going at 60 km/h and the other at 40 km/h. In how much time (in h) do they meet? (1) 2.0 (2) 2.5 (3) 3.0 (4) 3.3 (5) 4.0 Use the kinematic equation: x = x o + v o t + 1 at 2 for each car. Since neither car 2 accelerates the acceleration term vanishes. Have one car (speed P) cross the origin goi...
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