7 m s the second part involves mechanical energy

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Unformatted text preview: e kit before it splits. Thus the speed of the 4.0- kg kit is Px2 + Py2 P v= = = M M (8.66 kg ⋅ m/s ) + (11 kg ⋅ m/s ) 2 4.0 kg 2 = 3.5 m/s. 9P52. We think of this as having two parts: the first is the collision itself – where the bullet passes through the block so quickly that the block has not had time to move through any distance yet – and then the subsequent “leap” of the block into the air (up to height h measured from its initial position). The first part involves momentum conservation (with +y upward): ! ( 0.01kg )(1000 m s ) = ( 5.0 kg ) v + ( 0.01kg )( 400 m s ) ! which yields v = 1.2 m s . The second part involves either the free- fall e...
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This document was uploaded on 03/24/2014.

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